Abstract:This clear and concise advanced textbook is a comprehensive introduction to power electronics. It considers the topics of analogue electronics, electric motor control and adjustable speed electrical drives, both a.c. and d.c. In recent years, great changes have taken place in the types of semiconductor devices used as power switches in engineering applications. In this second edition of a popular text, a further completely new chapter has been added, dealing with the application of PWM techniques in induction … Show more
“…The two main component of the power losses in a bi-directional switch are conduction losses and switching losses. The formulation for semiconductor switch power losses calculating are well established in the literatures and maybe readily applied [12]. However, in this paper the on-state voltage drop and switching losses are neglected for simplicity.…”
Section: The Proposed Multilevel Convertermentioning
“…The two main component of the power losses in a bi-directional switch are conduction losses and switching losses. The formulation for semiconductor switch power losses calculating are well established in the literatures and maybe readily applied [12]. However, in this paper the on-state voltage drop and switching losses are neglected for simplicity.…”
Section: The Proposed Multilevel Convertermentioning
“…The triac is switched on by the gate current while the diac is turned on by the voltage applied to terminals. Shepherd, Hulley, and Liang (1995) stated the most important factors for making the optimal choice of power switch are the voltage and current ratings. Laster (1981) concluded that the key to selecting a proper thyristor is the consultation of the manufacturersÕ specification sheets based on the load characteristics such as voltage, current and power.…”
Section: Selection Of Triac and Diac Thyristorsmentioning
“…In general, G 1 (s) may be replaced by a real gain because the channel electronics is much faster than the whole motor loop. The motor is of a DC type [62,98] and therefore Kt Hmot(s) == ( )( ) sLa + Ra sJrot + D + KeKt (4.5) when considered between the input voltage and output angular frequency.…”
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