2019
DOI: 10.1002/cphc.201900030
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Possible Routes for Efficient Thermo‐Electric Energy Conversion in a Molecular Junction

Abstract: In the context of designing an efficient thermoelectric energy‐conversion device at nanoscale level, we suggest several important tuning parameters to enhance the performance of thermoelectric converters. We consider a simple molecular junction, which is always helpful to understand the basic mechanisms in a deeper way, where a benzene molecule is coupled to two external baths having unequal temperatures. The key component responsible for achieving better performance is associated with the asymmetric nature of… Show more

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Cited by 13 publications
(12 citation statements)
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“…Now, whenever we talk about the thermoelectric energy conversion, we need to focus on the conversion efficiency which is measured by the quantity figure of merit , usually referred as ZT . To make the device competitive with present thermoelectric devices, ZT should be at least comparable to unity, and, higher value of ZT (ZT>1 ) is thus always favorable.…”
Section: Introductionmentioning
confidence: 99%
“…Now, whenever we talk about the thermoelectric energy conversion, we need to focus on the conversion efficiency which is measured by the quantity figure of merit , usually referred as ZT . To make the device competitive with present thermoelectric devices, ZT should be at least comparable to unity, and, higher value of ZT (ZT>1 ) is thus always favorable.…”
Section: Introductionmentioning
confidence: 99%
“…we compute S , G , and K el following the Landauer integrals. [ 42–44 ] These are given by Sbadbreak=L1eTL0\begin{equation} S=-\frac{ L_1}{e T L_0} \end{equation} Gbadbreak=2e2L0\begin{equation} G=2 e^2 L_0 \end{equation} Kelbadbreak=2T()L2L12L0\begin{equation} K_{\text{el}}=\frac{2}{T}{\left(L_2-\frac{L_{1}^2}{L_0}\right)} \end{equation}The different quantities L n ( n = 0, 1, 2), used in above equations, are determined from the expression Lnbadbreak=1hτ(E)()fTfalse(EEffalse)nnormaldE\begin{equation} L_{n}=-\frac{1}{h} \int \limits _{-\infty }^{\infty }\tau (E){\left(\frac{\partial f}{\partial T}\right)} (E-E_\text{f})^{n} {\text{d}}E \end{equation}where f ( E ) is the Fermi–Dirac distribution function and E f is the equilibrium Fermi energy.…”
Section: Quantum System and The Methodsmentioning
confidence: 99%
“…The quantities G, S and k el are computed from the Landauer integrals through the relations [18,19,38,39] G = 2e 2 L 0 (8)…”
Section: Electrical Conductance Thermopower Electronic Thermal Conduc...mentioning
confidence: 99%
“…The fundamental mechanism of getting a favorable response relies on how much the transmission function is asymmetric across the energy around which the response is being determined. [18,19] More asymmetricity yields a more favorable response. Compared to different propositions available in the literature, in the present manuscript, we provide a new prescription that is quite interesting and important as well.…”
Section: Introductionmentioning
confidence: 99%
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