2008
DOI: 10.1103/physreve.77.036402
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Positive and negative effective mass of classical particles in oscillatory and static fields

Abstract: A classical particle oscillating in an arbitrary high-frequency or static field effectively exhibits a modified rest mass m eff derived from the particle averaged Lagrangian. Relativistic ponderomotive and diamagnetic forces, as well as magnetic drifts, are obtained from the m eff dependence on the guiding center location and velocity. The effective mass is not necessarily positive and can result in backward acceleration when an additional perturbation force is applied. As an example, adiabatic dynamics with m… Show more

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Cited by 42 publications
(46 citation statements)
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“…(77) in terms of Lorentz-invariant proper parameters of the medium [141]. Since Φ that enters here depends on the wave intensity, it must be gauge-invariant; thus, being (minus) the interaction Lagrangian of a single element, it transforms as Φ = Φ ′ /γ [142], with primes in this section (Sec. V) denoting the medium rest frame, and γ = (1 − v 2 /c 2 ) −1/2 .…”
Section: B Wave Energy-momentum In Isotropic Mediummentioning
confidence: 99%
“…(77) in terms of Lorentz-invariant proper parameters of the medium [141]. Since Φ that enters here depends on the wave intensity, it must be gauge-invariant; thus, being (minus) the interaction Lagrangian of a single element, it transforms as Φ = Φ ′ /γ [142], with primes in this section (Sec. V) denoting the medium rest frame, and γ = (1 − v 2 /c 2 ) −1/2 .…”
Section: B Wave Energy-momentum In Isotropic Mediummentioning
confidence: 99%
“…Also, Q = P ⊥ /(mc) is the normalized canonical momentum transverse to the direction of the pulse propagation; a = eA/(mc 2 ) is the laser parameter (the term proportional to a 2 is due to the laser ponderomotive potential [20,[29][30][31][32][33][34]); Π is a constant, which is determined by initial conditions and, for a particle outside the pulse, equals…”
mentioning
confidence: 99%
“…(77) in terms of Lorentz-invariant proper parameters of the medium [138]. Since Φ that enters here depends on the wave intensity, it must be gauge-invariant; thus, being (minus) the interaction Lagrangian of a single element, it transforms as Φ = Φ /γ [139], with primes in this section (Sec. V) denoting the medium rest frame, and γ = (1 − v 2 /c 2 ) −1/2 .…”
Section: B Wave Energy-momentum In Isotropic Mediummentioning
confidence: 99%