2021
DOI: 10.1007/978-3-030-60535-3
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Polynomial Automorphisms and the Jacobian Conjecture

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Cited by 205 publications
(105 citation statements)
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“…Note that (Φ( 1 )( ), … , Φ( )( )) = (Φ( 1 )( ), … , Φ( )( )), and this implies that the compounds are equal, so Φ( )( ) = Φ( )( ) for each , but the map Φ is injective so ( ) = ( ) for each ∈ {1, … , } this shows that = for each ∈ {1, … , } which implies that = which means that must be injective. Using the results from 10 , it can be seen that is invertible, and this completes our proof.…”
Section: Discussionsupporting
confidence: 62%
“…Note that (Φ( 1 )( ), … , Φ( )( )) = (Φ( 1 )( ), … , Φ( )( )), and this implies that the compounds are equal, so Φ( )( ) = Φ( )( ) for each , but the map Φ is injective so ( ) = ( ) for each ∈ {1, … , } this shows that = for each ∈ {1, … , } which implies that = which means that must be injective. Using the results from 10 , it can be seen that is invertible, and this completes our proof.…”
Section: Discussionsupporting
confidence: 62%
“…An invertibility criterion for endomorphisms of polynomial algebras can be obtained in terms of symbolic computation and Gröbner bases. For a comprehensive reference we refer to the book [25].…”
Section: Difference Stream Ciphersmentioning
confidence: 99%
“…In particular, it is known that if a polynomial map P : C n → C n is injective, then it is surjective and so is a polynomial automorphism. For more details on this open problem, we refer the reader to the survey paper [26].…”
Section: Analytic Automorphisms Of Subspaces Of C Nmentioning
confidence: 99%