2010
DOI: 10.1016/j.ejc.2009.11.013
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Planar graphs are 1-relaxed, 4-choosable

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Cited by 47 publications
(43 citation statements)
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“…Label the vertices of U as b 1 , b 2 , b 3 in such a way that b 3 does not have the same color as either b 1 or b 2 , which is possible since the colors of these three vertices are not all equal. Then the result is exactly Theorem 2(A) of [4].…”
Section: (4 1) * -Coloringsmentioning
confidence: 73%
“…Label the vertices of U as b 1 , b 2 , b 3 in such a way that b 3 does not have the same color as either b 1 or b 2 , which is possible since the colors of these three vertices are not all equal. Then the result is exactly Theorem 2(A) of [4].…”
Section: (4 1) * -Coloringsmentioning
confidence: 73%
“…For the rest of the proof we assume that every vertex x in layers L 1 , L 2 of D(l, k) has at most 14 bad neighbors in P j (x), j ∈ [2]. Let x be a good vertex in L 2 (such a vertex x exists as k > 14) and let y be any neighbor of x in L 2 .…”
Section: Lister's Strategymentioning
confidence: 99%
“…They both asked the question whether every planar graph is 1-defective 4-choosable. One decade later, Cushing and Kierstead [4] answered this question in the affirmative.…”
Section: Introductionmentioning
confidence: 99%