2009
DOI: 10.1142/s0217979209053862
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Photon in the Frame of the Current Loop Model

Abstract: We show that the electron–positron annihilation process ending with the creation of two gamma photons (with right- and left-hand circular helicity) can be explained in terms of the current loop model. We first show that both electron and positron (which are spin 1/2 particles) carry an intrinsic flux quantum of ±Φ0/2 even in the absence of an external magnetic field. By using the conservation of the magnetic flux quanta for collisions, we then argue that photon also carries a magnetic flux quantum of ±Φ0 = ±(h… Show more

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Cited by 12 publications
(16 citation statements)
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“…The definition of the canonical angular momentum vector, c J , for a free particle with charge q and the position vector r is given by [1]:…”
Section: Canonical Angular Momentum Of a Free Electron And A Positronmentioning
confidence: 99%
See 3 more Smart Citations
“…The definition of the canonical angular momentum vector, c J , for a free particle with charge q and the position vector r is given by [1]:…”
Section: Canonical Angular Momentum Of a Free Electron And A Positronmentioning
confidence: 99%
“…To calculate the canonical angular momentum of a gamma photon (γ) our starting point will be the electron-positron annihilation process ending with the creation of two gamma photons with ( ) rh and ( ) Ih circular helicities [1]. We will assume that electron and positron collide at the origin of the coordinate system.…”
Section: Canonical Angular Momenta Of Gamma Photonsmentioning
confidence: 99%
See 2 more Smart Citations
“…In an earlier study [1], we calculated the intrinsic quantum flux of a photon through the intrinsic quantum flux of the gamma photons created as a result of the electron-positron ( e − -e + ) annihilation. By using the flux conservation rule, which is an element of the conservation of the canonical angular momentum, we find that each gamma photon carries a magnetic flux quantum of 0 hc e ±Φ = ± with itself along the propagation direction.…”
Section: Introductionmentioning
confidence: 99%