2005
DOI: 10.1016/j.physb.2004.11.070
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Phonon hardening due to the small-polaron effect

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Cited by 12 publications
(3 citation statements)
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“…This point appears by the consequence of the fact that the SP dressing fraction (and consequently quasiparticle effective mass) increases as temperature grows, but it also increases with the increases of coupling constant value. [38] On the other hand, for small and medium values of S our results significantly differ from those predicted by standard LF theory. In contrast to the standard SP theory, in that limit our approach predicts slightly dressed or partially dressed vibron states (instead of characteristic parabolic shape, the adiabatic curves E GS (S) has linear dependence of coupling constant).…”
Section: E Gcontrasting
confidence: 77%
See 1 more Smart Citation
“…This point appears by the consequence of the fact that the SP dressing fraction (and consequently quasiparticle effective mass) increases as temperature grows, but it also increases with the increases of coupling constant value. [38] On the other hand, for small and medium values of S our results significantly differ from those predicted by standard LF theory. In contrast to the standard SP theory, in that limit our approach predicts slightly dressed or partially dressed vibron states (instead of characteristic parabolic shape, the adiabatic curves E GS (S) has linear dependence of coupling constant).…”
Section: E Gcontrasting
confidence: 77%
“…These observations seem to be not surprising, because of the framework of the standard small-polaron approach, the growth of the system temperature has practically the same effect as the growth of the coupling constant. This point appears by the consequence of the fact that the SP dressing fraction (and consequently quasiparticle effective mass) increases as temperature grows, but it also increases with the growth of coupling constant value [38].…”
Section: Resultsmentioning
confidence: 99%
“…It is responsible for some important phenomena, SP mobility in particular, and deserves a separate examination. Some possible consequences have been examined within the strong-coupling approximation in [23]. The vibron operators are taken in the Fourier representation for convenience: a k = 1 √ N n e iknR 0 a n ,…”
Section: Theoretical Analysismentioning
confidence: 99%