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2008 IEEE International Conference on Communications 2008
DOI: 10.1109/icc.2008.829
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Performance Analysis of Dual-Hop OFDM Relay Systems with Subcarrier Mapping

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Cited by 38 publications
(26 citation statements)
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“…To show the proof of Theorem 1, we incorporate (8) into (16), and after further manipulation along with [3], it gives Pr γ eq < γ th = Pr…”
Section: B Outage Probabilitymentioning
confidence: 99%
See 1 more Smart Citation
“…To show the proof of Theorem 1, we incorporate (8) into (16), and after further manipulation along with [3], it gives Pr γ eq < γ th = Pr…”
Section: B Outage Probabilitymentioning
confidence: 99%
“…Subcarrier mapping at the relay has the potential to increase the OFDM capacity [2]. In [3], the authors proposed an exact analytical technique for evaluation the average capacity of a dual OFDM system subcarrier mapping at the relay which is based on results of [2]. The BER performance of the best-to-worst and the best-to-best subcarrier mapping for OFDM AF relaying system is studied in [4].…”
Section: Introductionmentioning
confidence: 99%
“…Adaptive relaying scheme for OFDM that taking channel state information into account has been proposed in (Herdin, 2006), where subcarrier matching was considered for OFDM amplify-and-forward scheme but the power allocation was not considered. Performances of OFDM dual-hop system with and without subcarrier matching were studied in (Suraweera & Armstrong, 2007) and (Athaudage et al, 2008), separately. The problems of resource allocation were considered in OFDMA cellular and OFDMA multihop system (Pischella & Belfiore, 2008) and (Kim et al, 2008).…”
Section: Soucementioning
confidence: 99%
“…This method has often been adopted in the literature, e.g. [9], [10], [12], [35], and [36], to better exploit diversity in the frequency domain. In the case without SP, the function is defined by…”
Section: System Model and Problem Formulationmentioning
confidence: 99%
“…Thus, the effective SNR, defined by ξ k Δ = P d /P v , can be computed as in (36), shown at the bottom of the next page, where 1/Λ 2 ϕ(k) = |Ĥ SR,k | 2 + SR,k + (1/γ d ), and ζ k is given in (9).…”
mentioning
confidence: 99%