“…Dendron 15 was prepared from alcohol 14 by following the general procedure for transforming alcohol into bromide with extended reaction time (24 h) and excess amount of PBr 3 (5 equivalent) as a white powder with an 85% yield. 1 H NMR (400 MHz, CDCl 3 ) δ 1.95-2.21 (m, 30H), 2.74-3.0 (m, 30H), 3.38 (t, J = 6 Hz, 2H), 3.46 (s, 48H), 3.63 (m, 28H), 7.47-7.61 (m, 30H), 7.65-7.76 (m, 15H); 13 C NMR (100 MHz, CDCl 3 ) δ 31 3,. 32.0, 32.1, 33.8, 54.3, 65.6, 65.7, 122.4 (q, J = 287.0 Hz), 125.9, 126.4, 129.3, 129.7, 130.2, 142.9, 143.1; 19 F NMR (376 MHz, CDCl 3 ) δ -73.92, -73.89.Dendrimer 1.A mixture of bromide 15 (4.9 g, 0.7 mmol), 1.l.l-tris(4'-hydroxyphenyl)ethane 4 (63.8 mg, 0.2 mmol), anhydrous K 2 CO 3 (115.1 mg, 0.8 mmol) and 18-crown-6 (16.5 mg, 0.06 mmol) in dry acetone (100 mL) was refluxed under an atmosphere of argon for 48 h. After the mixture was cooled toPage 16 of 19 ACS Paragon Plus Environment The Journal of Organic Chemistry…”