2022
DOI: 10.1007/978-3-031-15914-5_19
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Parameterized Complexity of Weighted Multicut in Trees

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Cited by 5 publications
(8 citation statements)
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“…Hence, Theorem 6 follows from the above lemma. Additionally, it is known that Dominating Set can be solved in time 2Ofalse(false)·nOfalse(1false)$$ {2}^{O\left(\ell \right)}\cdotp {n}^{O(1)} $$ on a chordal graph G$$ G $$, where =false(Gfalse)$$ \ell =\ell (G) $$ and n=false|Vfalse(Gfalse)false|$$ n=\mid V(G)\mid $$ [16]. Since the hypothesis of Lemma 2 applies to Dominating Set , we get that it can be solved in time 2Ofalse(κ·vfalse(Gfalse)false)·nOfalse(1false)$$ {2}^{O\left(\kappa \cdotp v\mathit{\ell}(G)\right)}\cdotp {n}^{O(1)} $$ on a chordal graph, provided the appropriate model is given, that is, the part of Theorem 2 concerning Dominating Set follows.…”
Section: Proof Of Part Of Theorem 2 and Of Theoremmentioning
confidence: 99%
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“…Hence, Theorem 6 follows from the above lemma. Additionally, it is known that Dominating Set can be solved in time 2Ofalse(false)·nOfalse(1false)$$ {2}^{O\left(\ell \right)}\cdotp {n}^{O(1)} $$ on a chordal graph G$$ G $$, where =false(Gfalse)$$ \ell =\ell (G) $$ and n=false|Vfalse(Gfalse)false|$$ n=\mid V(G)\mid $$ [16]. Since the hypothesis of Lemma 2 applies to Dominating Set , we get that it can be solved in time 2Ofalse(κ·vfalse(Gfalse)false)·nOfalse(1false)$$ {2}^{O\left(\kappa \cdotp v\mathit{\ell}(G)\right)}\cdotp {n}^{O(1)} $$ on a chordal graph, provided the appropriate model is given, that is, the part of Theorem 2 concerning Dominating Set follows.…”
Section: Proof Of Part Of Theorem 2 and Of Theoremmentioning
confidence: 99%
“…We now prove the part of this theorem concerning Dominating Set and the remainder follows from Theorem 3, which we prove in Sections 5 and 6. Even though this complexity is worse than the one achieved by Theorem 2, we propose this algorithm for its simplicity when compared to the one presented in [16] that we used to conclude Theorem 2.…”
Section: Proof Of Part Of Theoremmentioning
confidence: 99%
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