“…It can be observed that for the scenarios when each SU-TX is located at equal distance from eNodeB and PU-RX, each SU-TX has equal probability of being selected for transmission. 3 The integral in (13) and (18) are solved for the scenario where a = b = c. Therefore, for simulation purposes, we considered d SD,k ≈ d SP,k ≈ 2 ∀k, where d SD,1 = 2.002, d SD,2 = 2.004, d SD,3 = 2.006, d SP,1 = 2.001, d SP,2 = 2.003, and d SP,3 = 2.005. For the scenario, when 2nd SU-TX is closer to the eN-odeB than the PU-RX, i.e., d SP,k ≈ d SD,k ≈ 2, ∀k except d SD,2 ≈ 1 as shown in Fig.…”