2017
DOI: 10.1109/tac.2016.2642794
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Optimized State Space Grids for Abstractions

Abstract: The practical impact of abstraction-based controller synthesis methods is currently limited by the immense computational effort for obtaining abstractions. In this note we focus on a recently proposed method to compute abstractions whose state space is a cover of the state space of the plant by congruent hyper-intervals. The problem of how to choose the size of the hyper-intervals so as to obtain computable and useful abstractions is unsolved. This note provides a twofold contribution towards a solution. First… Show more

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Cited by 20 publications
(12 citation statements)
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“…A common first step for symbolic controller synthesis requires abstracting the control system with a continuous state and input space into one with discrete states and inputs. However, this abstraction step has been cited as a key bottleneck in benchmarks for higher-dimensional systems [1] [2]. Many abstraction procedures implemented in current tools traverse the state space in a brute force manner and suffer from an exponential runtime with respect to the sum of state and input dimensions.…”
Section: Introductionmentioning
confidence: 99%
“…A common first step for symbolic controller synthesis requires abstracting the control system with a continuous state and input space into one with discrete states and inputs. However, this abstraction step has been cited as a key bottleneck in benchmarks for higher-dimensional systems [1] [2]. Many abstraction procedures implemented in current tools traverse the state space in a brute force manner and suffer from an exponential runtime with respect to the sum of state and input dimensions.…”
Section: Introductionmentioning
confidence: 99%
“…Then, from Lemma 4, there exists q ∈ ∆(q 0 , u 0 ) such that q = (x(τ ), z(τ )) Q0 . By, (14) we also get that q ∈ dom(Θ), which in turn implies by (12) that (x(τ ), z(τ )) ∈ dom(g). Hence, the completeness condition (CC) is satisfied.…”
Section: Proofmentioning
confidence: 88%
“…∀q ∈ dom(Θ), ∀v ∈ Θ(q), ∆(q, v) ⊆ dom(Θ). (14) Let the control map g : X × Z ⇒ U be given by (12). Then, Σ |= s C andΣ satisfies (CC).…”
Section: Proofmentioning
confidence: 99%
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“…While the problem is found with all discretization based methods to solve (7), several strategies to somewhat relieve the computational burden that have been proposed, e.g. [53]- [55], could potentially be extended to our setting.…”
Section: Comments On Computational Complexitymentioning
confidence: 99%