1994
DOI: 10.1007/bf02571709
|View full text |Cite
|
Sign up to set email alerts
|

Open subgroups and Pontryagin duality

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1
1
1

Citation Types

0
16
0

Year Published

1996
1996
2016
2016

Publication Types

Select...
8
1

Relationship

0
9

Authors

Journals

citations
Cited by 26 publications
(16 citation statements)
references
References 4 publications
0
16
0
Order By: Relevance
“…Let f : G → K be a continuous homomorphism onto K, where K is either T c or Z(n) c . Since the homomorphism f is open, H = f −1 (P ) is a proper dense pseudocompact subgroup of G. The restriction ϕ = f ↾ H is an open continuous homomorphism with a compact kernel N. Since the image P = ϕ(H) ∼ = H/N is a reflexive group, we conclude that so is H (see [6,Theorem 2.6]).…”
Section: Remark 43mentioning
confidence: 84%
See 1 more Smart Citation
“…Let f : G → K be a continuous homomorphism onto K, where K is either T c or Z(n) c . Since the homomorphism f is open, H = f −1 (P ) is a proper dense pseudocompact subgroup of G. The restriction ϕ = f ↾ H is an open continuous homomorphism with a compact kernel N. Since the image P = ϕ(H) ∼ = H/N is a reflexive group, we conclude that so is H (see [6,Theorem 2.6]).…”
Section: Remark 43mentioning
confidence: 84%
“…Then H is a proper subgroup of G and, since the homomorphism f is open, H is dense in G. Let ϕ be the restriction of f to H.Then ϕ is open and ker f = ker ϕ, i.e., the homomorphism ϕ has the compact kernel N. Hence the group H is almost metrizable, while Lemma 3.5 implies that H is Baire. Since N is compact and the quotient group H 0 ∼ = H/N is not reflexive, neither is H (see[6, Theorem 2.6]). Note that H satisfies ORC according to Proposition 2.9.…”
mentioning
confidence: 99%
“…As it was noticed in [18] before Definition 2.33, for every T -sequence u in an infinite Abelian group G the subgroup u is open in (G, τ u ) (see also Lemma 2.2), and hence, by Lemmas 1.4 and 2.2 of [3], the following sequences are exact:…”
mentioning
confidence: 79%
“…Indeed, by definition, u k is a T -sequence and (G, u) = (G, u k ). Since, by definition, u k is open, it is dually closed and dually embedded [6]. By Lemma 4, we have n(G, u) ⊂ u k .…”
Section: Lemma 4 Let H Be a Dually Closed And Dually Embedded Subgromentioning
confidence: 92%