“…It is worth pointing out that ðða rÞ=ð2 N r À 1ÞÞðp=2Þ, the argument of the secant function in formula (3.2), is always in the interval ð0; p=2Þ, as proved in [3,Proposition 2]. Moreover, the only case for which ða rÞ=ð2 N r À 1Þ ¼ 1 is the one corresponding to the choice b 1 ¼ b 2 ¼ Á Á Á ¼ b N ¼ 1, which does not fulfill the requirements of Theorem 3.1.…”