2003
DOI: 10.1016/s0004-3702(02)00378-8
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On the undecidability of probabilistic planning and related stochastic optimization problems

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Cited by 198 publications
(213 citation statements)
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References 22 publications
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“…The proof of Paz is a reduction from an undecidable problem about free context grammars. An alternative proof was given by Madani, Hanks and Condon [10], based on a reduction from the emptiness problem for two counter machines. Since Paz was focusing on expressiveness aspects of probabilistic automata rather than on algorithmic questions, his undecidability proof is spread on the whole book [11], which makes it arguably hard to read.…”
Section: The Emptiness Problemmentioning
confidence: 99%
“…The proof of Paz is a reduction from an undecidable problem about free context grammars. An alternative proof was given by Madani, Hanks and Condon [10], based on a reduction from the emptiness problem for two counter machines. Since Paz was focusing on expressiveness aspects of probabilistic automata rather than on algorithmic questions, his undecidability proof is spread on the whole book [11], which makes it arguably hard to read.…”
Section: The Emptiness Problemmentioning
confidence: 99%
“…It is known that partially observable Markov Decision Processes are undecidable, even with finite state space (see [13]). With full observation, they become decidable; Monte-Carlo Tree Search (MCTS, [7]) is a recent well known solver for this case, with impressive results in many cases, in particular the game of Go [12].…”
Section: State Of the Art And Outline Of The Papermentioning
confidence: 99%
“…First consider (13). By Lemma 1, there is a integer p such that all children i = 1, · · · , i 0 − 1 have been selected p or p + 1 times, with p = O n 1−α .…”
Section: Consistency Of Random Nodesmentioning
confidence: 99%
“…The impact of partial observability in games and planning is studied in several papers, showing in particular that -Just one player and a random part makes the problem undecidable, even with a finite state space with reachability criteria [10]. -With two players with or without random parts, the problem is EXP, EXPSPACE, 2EXP (i.e.…”
Section: Introductionmentioning
confidence: 99%
“…For example, [10] has shown that with one player only, no observation, random nodes, the probability of winning, when starting in a given node, and for an optimal strategy, is not computable, and even not approximable. [14] has shown that this also holds for two players and no random node.…”
Section: Introductionmentioning
confidence: 99%