“…Passing to the limit as → 0 in(12) with the use of conditions T 3 (x, 0) ≡ 0 and T 4 (x, 0) ≡ 1, we obtain(x, 0) ≡ C(0) 3 (x, 0).By conditions (s−1) 0, ) = 3s , s = 1, 2, 3 and T 3 (0, ) = 0, it follows from the first part of Lemma 2.1 that 3 (x, ) > 0, ′ 3 (x, ) > 0 for x ∈ (0, 1] and > 0. Then by Lemmas 3.2 and 3.8, we have 3 (x, 0) ≠ 0 and ′ 3 (x, 0) ≠ 0 for x ∈ (0, 1].…”