“…The reason is that the circularity condition assumed by them is not consistent with out assumption n"N, as the following argument shows. With out notation, a pair (qK, k) is circular (as defined in [10]) if the multiplicative subgroup satisfies " a#b 5 c#d"42 for all a, c 3GF(q)*, b, d3 GF(q) with aO c or bOd. Ke and Kiechle determined the number of solutions of the Fermat equation XL#½L#1"0 under the extra condition that (qK, (qK!1)/n) is circular.…”