2013
DOI: 10.1016/j.stamet.2013.04.003
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On the simple step-stress model for two-parameter exponential distribution

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Cited by 25 publications
(9 citation statements)
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“…Notice that, although the joint CDF of (μ,σ ) can be expressed in closed form in the non-adaptive case, exact inference does not work as usual since the distribution ofσ is not stochastically monotone in σ in general. This was noticed in [15] in a different context involving E (μ, σ ), but it is true here, too.…”
Section: Example 4 For the Two-parameter Exponential Distribution E (supporting
confidence: 68%
“…Notice that, although the joint CDF of (μ,σ ) can be expressed in closed form in the non-adaptive case, exact inference does not work as usual since the distribution ofσ is not stochastically monotone in σ in general. This was noticed in [15] in a different context involving E (μ, σ ), but it is true here, too.…”
Section: Example 4 For the Two-parameter Exponential Distribution E (supporting
confidence: 68%
“…In this case, one can assume that the mean lifetime under the stress level s2 is smaller than the mean lifetime at the stress level s1, which implies β1<β2. One way to investigate this case is to use restricted prior assumption, for more details one may refer to Mitra et al 19 and Ganguly et al 20 . In this paper, we assume the unrestricted prior assumption with joint prior density given by ().…”
Section: Bayesian Estimationmentioning
confidence: 99%
“…In order to incorporate the different testing levels in the model, we assume a cumulative exposure model as has been introduced in Sedyakin (1966) (see also Bagdonavičius, 1978; Nelson & Meeker, 1978). In fact, we follow the ideas developed in simple step‐stress testing as developed in, for example, Balakrishnan, Kundu, Ng, and Kannan (2007), Balakrishnan, Xie, and Kundu (2009), Kateri, Kamps, and Balakrishnan (2009), Mitra, Ganguly, Samanta, and Kundu (2013) (for reviews, see Balakrishnan 2009; Gouno & Balakrishnan, 2001; Kundu & Ganguly, 2017) where a similar idea has been successfully utilized. In our setting, we consider distribution functions F 0 , F 1 , … , F k − 1 corresponding to stages s 0 , s 1 , … , s k − 1 .…”
Section: Introductionmentioning
confidence: 99%