1929
DOI: 10.2307/2370712
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On the Problem of Existence of Algebraic Functions of Two Variables Possessing a Given Branch Curve

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Cited by 242 publications
(225 citation statements)
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“…Suppose t = 0; then Σ is r + 1 lines in general position and π 1 (CP 2 \ Σ) ∼ = A r , where A r is a free abelian group on r generators [7].…”
Section: π 1 Of Complements Of Some Line Arrangementsmentioning
confidence: 99%
See 1 more Smart Citation
“…Suppose t = 0; then Σ is r + 1 lines in general position and π 1 (CP 2 \ Σ) ∼ = A r , where A r is a free abelian group on r generators [7].…”
Section: π 1 Of Complements Of Some Line Arrangementsmentioning
confidence: 99%
“…In [7], Zariski showed that the fundamental group of the complement of an irreducible sextic curve in the projective plane with six cusps lying on a conic is isomorphic to the free product of Z 2 and Z 3 (see also [4]). In [8], he then showed that the complement of an irreducible sextic curve with six cusps that do not lie on a conic has abelian fundamental group.…”
Section: Introductionmentioning
confidence: 99%
“…A different direction for the need of fundamental groups' computations is for getting more examples of Zariski pairs [36,37]. A pair of plane curves is called a Zariski pair if they have the same combinatorics (i.e.…”
Section: Introductionmentioning
confidence: 99%
“…We let c, be an irreducible sextic with six cusps on a conic. In this case it can be shown (Zariski [6]) that ttx(P2 -cx) = <g" g2; g2, g|>. We let c2 be an irreducible nonsingular sextic.…”
mentioning
confidence: 99%
“…In this case H = Z/4 Z and it can be shown that 77,(P2 -c,) = <g" g2; g\g22, g\, (gxg2?gx~2) (cf. Zariski [6]). We have the following result.…”
mentioning
confidence: 99%