“…Because λ = (6, 5, 3, 1, 1), it follows that α Y = (12,11,9,7,7,6,5,3,1,1). Then the shifts in the bigraded minimal free resolution of I Y are given by SY 0 = {(10, 0), (8, 1), (7, 3), (6,5), (5,6), (3,7), (2,9), (1,11), (0, 12)} SY 1 = {(10, 1), (8, 3), (7,5), (6,6), (5,7), (3,9), (2,11), (1, 12)}.…”