2007
DOI: 10.1090/s0002-9939-07-08733-3
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On the poles of the resolvent in Calkin algebra

Abstract: In the present note, we study the problem of lifting poles in Calkin algebra on a separable infinite-dimensional complex Hilbert space H. We show by an example that such lifting is not possible in general, and we prove that if zero is a pole of the resolvent of the image of an operator T in the Calkin algebra, then there exists a compact operator K for which zero is a pole of T + K if and only if the index of T − λ is zero on a punctured neighbourhood of zero. Further, a useful characterization of poles in Cal… Show more

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Cited by 4 publications
(4 citation statements)
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“…The answer is that this happens if and only if R(T n ) and R(T n+1 ) are closed. With the answer to those questions, we retrieve in particular some similar results established in the case of Hilbert spaces in [4].…”
Section: Introductionmentioning
confidence: 65%
“…The answer is that this happens if and only if R(T n ) and R(T n+1 ) are closed. With the answer to those questions, we retrieve in particular some similar results established in the case of Hilbert spaces in [4].…”
Section: Introductionmentioning
confidence: 65%
“…In the article [6], given a separable infinite dimensional Hilbert space H and T ∈ L(H), it was characterized when zero is a pole of the resolvent of π(T ) ∈ C(H) in terms of the operator T ∈ L(H), where C(H) is the Calkin algebra and π : L(H) → C(H) is the quotient map. In fact, zero is a pole of the resolvent of π(T ) ∈ C(H) if and only if there are operators A, B and K ∈ L(H) such that A is nilpotent, B is Fredholm, K is compact and T = A ⊕ B + K (see [6,Theorem 2.2]).…”
Section: Introductionmentioning
confidence: 99%
“…In the article [6], given a separable infinite dimensional Hilbert space H and T ∈ L(H), it was characterized when zero is a pole of the resolvent of π(T ) ∈ C(H) in terms of the operator T ∈ L(H), where C(H) is the Calkin algebra and π : L(H) → C(H) is the quotient map. In fact, zero is a pole of the resolvent of π(T ) ∈ C(H) if and only if there are operators A, B and K ∈ L(H) such that A is nilpotent, B is Fredholm, K is compact and T = A ⊕ B + K (see [6,Theorem 2.2]). It is worth noticing that according to [32,Proposition 1.5] or [10,Theorem 12], given a complex unital Banach algebra A, the set of the poles of the resolvent of a ∈ A coincide with {λ ∈ iso σ(a) : such that a − λ1 is Drazin invertible}, where iso σ(a) denotes the set of isolated points of the spectrum σ(a) and 1 ∈ A denotes the identity of A.…”
Section: Introductionmentioning
confidence: 99%
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