1989
DOI: 10.2307/2001141
|View full text |Cite
|
Sign up to set email alerts
|

On the Linear Representation of Braid Groups

Abstract: Abstract.We give a new derivative of the Burau and Gassner representations of the braid and pure braid groups. Various applications are explored.

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1
1
1
1

Citation Types

0
6
0

Year Published

1989
1989
2016
2016

Publication Types

Select...
6

Relationship

0
6

Authors

Journals

citations
Cited by 8 publications
(6 citation statements)
references
References 2 publications
0
6
0
Order By: Relevance
“…[1] At the beginning of this subsection, we have verified that the conditions of Lemma 7 are satisfied. By the result of [12] quoted earlier, Ω n admits a nondegenerate hermitian form. Therefore, by Lemma 7, the representation g n (X) is absolutely irreducible.…”
Section: 2mentioning
confidence: 76%
See 2 more Smart Citations
“…[1] At the beginning of this subsection, we have verified that the conditions of Lemma 7 are satisfied. By the result of [12] quoted earlier, Ω n admits a nondegenerate hermitian form. Therefore, by Lemma 7, the representation g n (X) is absolutely irreducible.…”
Section: 2mentioning
confidence: 76%
“…We first construct (in subsection 4.1) a skew Hermitian form on the reduced Gassner representation, which is invariant under the action of the pure braid group. The existence of the form is due to [12] (see also [8]) , but the construction for the basis ε i defined in the previous section, may perhaps be new. Using this form, it is easy to decide when specialisations of the Gassner representation (especially d-th roots of unity) are irreducible.…”
Section: Properties Of the The Gassner Representationmentioning
confidence: 99%
See 1 more Smart Citation
“…Since β = β 1 β 2 is a split braid with β 1 ∈ B k 1 , by (2) we have that β(X) 1 · · · β(X) k 1 = β 1 (X) 1 · · · β 1 (X) k 1 = X 1 · · · X k 1 , and this implies X 1 · · · X k 1 = ω a 1 +···+an 1 X 1 · · · X k 1 . But ω a 1 +···+an 1 = 1 by the assumption of Equation (15), and this gives the desired contradiction.…”
Section: Split Linksmentioning
confidence: 93%
“…, x n . We will follow the conventions of [10] and define the n-string braid group B n to be the subgroup of Aut(F n ) generated by the automorphisms σ 1 , . .…”
Section: Braids and Representationsmentioning
confidence: 99%