2009
DOI: 10.1134/s0081543809070219
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On the intersections of solvable Hall subgroups in finite groups

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Cited by 6 publications
(7 citation statements)
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“…Theorem 1 reduces both parts of Problem 1 to the investigation of almost simple groups. Notice also that Theorem 1 generalizes the main result of [11] in the following way.…”
Section: Introductionsupporting
confidence: 62%
See 1 more Smart Citation
“…Theorem 1 reduces both parts of Problem 1 to the investigation of almost simple groups. Notice also that Theorem 1 generalizes the main result of [11] in the following way.…”
Section: Introductionsupporting
confidence: 62%
“…V.I.Zenkov in [12] constructed an example of a group G with a solvable π-Hall subgroup H such that the intersection of five subgroups conjugate with H in G is equal to O π (G), while the intersection of every four conjugates of H is greater than O π (G) (see Example 9 below). In [11] it is proven that if, for every almost simple group S possessing a solvable π-Hall subgroup H, the inequalities Base H (S ) 5 and Reg H (S , 5) 5 hold, then for every group G possessing a solvable π-Hall subgroup H the inequality Base H (G) 5 holds. In the present paper we prove the following Theorem 1.…”
Section: Introductionmentioning
confidence: 99%
“…As noted in [4, Lemma 3], if b(G, H) 4 then G has at least 5 regular orbits on Ω 5 , so Theorem 1 establishes the desired condition for all almost simple sporadic groups (in a strong form), bringing us a step closer to a proof of Vdovin's conjecture. It also extends a special case of a theorem of Vdovin and Zenkov [33,Theorem 2], which states that b(G, H) 5 when G is an almost simple sporadic group and H is a soluble π-Hall subgroup of G.…”
Section: Introductionmentioning
confidence: 60%
“…In case (a), the proof of [57,Theorem 2] gives reg(L, 5) 12 and thus b(G, H) 5 as required. In fact, a straightforward Magma computation shows that reg(L, 5) = 600 in this case.…”
Section: Exceptional Groups: Non-parabolic Actionsmentioning
confidence: 95%