“…When r = 1 and l 3, there are no (r, l) + -identifying codes, because always I 1 ((0, 0), (0, 2), (2, 1)) = I 1 ((0, 0), (0, 2), (2, 1), (1, 1)). The code C = Z 2 is (1, 3)-identifying (see [10]), and therefore (1, 2) + -identifying (see Theorem 4). No proper subset of Z 2 is (1, 2) + -identifying: if, e.g., (1, 1) / ∈ C, then I 1 ((0, 0), (2, 2)) = I 1 ((0, 0), (1, 1), (2, 2)).…”