Abstract:Abstract. Suppose g and h are entire functions with the order of h less than the order of g . If the order of g does not exceed j , it is shown that every (necessarily entire) nonconstant solution / of the differential equation f" + gf + hf = 0 has infinite order. This result extends previous work of Ozawa and Gundersen.
“…where A(z), B(z) and F (z) are entire in C. Since 1982, great progress have been achieved on the global theory of (1), see [14,6,7,10,11,13,2,3]. However, the research on the properties of solutions in an angle is not so active.…”
“…where A(z), B(z) and F (z) are entire in C. Since 1982, great progress have been achieved on the global theory of (1), see [14,6,7,10,11,13,2,3]. However, the research on the properties of solutions in an angle is not so active.…”
“…It is well known that if either σ (B) < σ (A) or σ (A) < σ (B) 1/2, then every solution f ≡ 0 of (1.1) is of infinite order (see [9,13]). For the case σ (A) < σ (B) and σ (B) > 1/2, many authors have studied the problem.…”
In this paper, the authors investigate the growth of solutions of a class of higher order linear differential equationswhen most coefficients in the above equations have the same order with each other, and obtain some results which improve previous results due to K.H. Kwon [K.H. Kwon, Nonexistence of finite order solutions of certain second order linear differential equations, Kodai Math.
“…There has been much work on this subject. For example, it follows from the work by Gunderson [10], Hellerstein, Miles and Rossi [12] that if A(z) and B(z) are entire functions with ρ(A) < ρ(B); or if A(z) is a polynomial, and B(z) is transcendental; or if ρ(B) < ρ(A) 1 2 , then every solution f ≡ 0 of the equation (1.1) has infinite order.…”
In this paper, we consider the differential equation f + Af + Bf = 0, where A(z) and B(z) ≡ 0 are entire functions. Assume that A(z) has a finite deficient value, then we will give some conditions on B(z) which can guarantee that every solution f ≡ 0 of the equation has infinite order.
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