1993
DOI: 10.1006/jnth.1993.1041
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On the Equations px − by = c and ax + by = cz

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Cited by 42 publications
(76 citation statements)
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“…In [3], Bennett handles Theorem A for the case a prime by using results from [14], but this will not work here since we are allowing the exponents x and y to be zero. Instead, we will use a result of Luca [11] on the equation p r ± p s + 1 = z 2 , where p, r, s, and z are positive integers with p prime.…”
Section: Proof Of Theoremmentioning
confidence: 99%
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“…In [3], Bennett handles Theorem A for the case a prime by using results from [14], but this will not work here since we are allowing the exponents x and y to be zero. Instead, we will use a result of Luca [11] on the equation p r ± p s + 1 = z 2 , where p, r, s, and z are positive integers with p prime.…”
Section: Proof Of Theoremmentioning
confidence: 99%
“…We apply Theorem 3 of [14] which states that, when a is prime and the parity of y is fixed, Equation (1.1) has at most one solution in positive integers (x, y) except for the following five exceptional (a, b, c; x 1 , y 1 , x 2 , y 2 ): (3, 2, 1; 1, 1, 2, 3), (2, 3, 5; 3, 1, 5, 3), (2, 3, 13; 4, 1, 8, 5), (2, 5, 3; 3, 1, 7, 3), (13, 3, 10; 1, 1, 3, 7). Noting that none of these five exceptional cases has a further solution with 2 | y > 0 (use congruences modulo 3 or modulo 8), we see that, if (1.2) has more than two solutions in nonnegative integers x and y when a is prime, we must have exactly one solution with y = 0 and exactly two further solutions.…”
Section: Proof Of Theoremmentioning
confidence: 99%
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