2021
DOI: 10.1007/s00023-021-01058-9
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On the Domains of Bessel Operators

Abstract: We consider the Schrödinger operator on the halfline with the potential $$(m^2-\frac{1}{4})\frac{1}{x^2}$$ ( m 2 - 1 4 ) 1 x … Show more

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Cited by 12 publications
(11 citation statements)
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“…Concerning A α (0), it suffices to import from the literature the following analogue of Lemma 5.11. Proof A direct consequence of [77,Theorem 4.1]: in the notation therein A α (0) is the operator L min δ with δ − 1 4 = C α (the present δ replaces the notation α from [77] so as not to clash with the current meaning of α), that is δ = ( 1+α 2 ) 2 ; the requirement Re √ δ < 1 needed for the applicability of [77, Theorem 4.1] is therefore satisfied, since α ∈ (0, 1).…”
Section: One-sided Extensions For the Zero Modementioning
confidence: 91%
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“…Concerning A α (0), it suffices to import from the literature the following analogue of Lemma 5.11. Proof A direct consequence of [77,Theorem 4.1]: in the notation therein A α (0) is the operator L min δ with δ − 1 4 = C α (the present δ replaces the notation α from [77] so as not to clash with the current meaning of α), that is δ = ( 1+α 2 ) 2 ; the requirement Re √ δ < 1 needed for the applicability of [77, Theorem 4.1] is therefore satisfied, since α ∈ (0, 1).…”
Section: One-sided Extensions For the Zero Modementioning
confidence: 91%
“…The characterisation of the distinguished extension of h declared in Proposition 4.3 goes through the differential problem h f = g in the unknown f for given g ∈ L 2 (R + , C), so as to determine the domain of invertibility of the differential operator h. The strategy here is an adaptation to the present first order differential operator with Coulomb singularity of the analogous problem for homogeneous Schrödinger operators of Bessel type on half-line, a subject that is well classical [51,77] and which is also encountered, in a different context, in Sections 3.2.1, 5.6 and 5.8.6.…”
Section: Distinguished Extension H Dmentioning
confidence: 99%
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“…implying S * 0,min = S 0,max , S * 0,max = S 0,min , and we also introduce the following self-adjoint extensions of S 0,min , respectively, restrictions of S 0,max (see, e.g., [3], [5], [4], [11], [15], [19], [24], [28], [38], [40], [56]),…”
Section: A Refinement Of Hardy's Inequalitymentioning
confidence: 99%