1990
DOI: 10.1017/s0305004100068936
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On the computational complexity of the Jones and Tutte polynomials

Abstract: We show that determining the Jones polynomial of an alternating link is #P-hard. This is a special case of a wide range of results on the general intractability of the evaluation of the Tutte polynomial T(M; x, y) of a matroid M except for a few listed special points and curves of the (x, t/)-plane. In particular the problem of evaluating the Tutte polynomial of a graph at a point in the (x, y) -plane is #P-hard except when (x-l)(y-l) = l or when (x,y) equals (

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Cited by 406 publications
(423 citation statements)
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“…This was shown by Jaeger, Vertigan and Welsh [JVW90]. They proved that for any primitive root of unity e 2πi/n , n > 4 and n = 6, the evaluation of the Jones polynomial at this value is #P -hard.…”
Section: Complexity Theorymentioning
confidence: 83%
See 1 more Smart Citation
“…This was shown by Jaeger, Vertigan and Welsh [JVW90]. They proved that for any primitive root of unity e 2πi/n , n > 4 and n = 6, the evaluation of the Jones polynomial at this value is #P -hard.…”
Section: Complexity Theorymentioning
confidence: 83%
“…The Alexander polynomial is computable in polynomial time in the number of crossings of a knot while evaluations of the Jones polynomial at all but eight points are known to be #P -hard [JVW90].…”
Section: Introductionmentioning
confidence: 99%
“…The case where q = 3 is more interesting. A classical algorithm to compute this invariant exists which works in a time that scales polynomially with the number of crossings [26]. In turn, using a generalisation to three-level systems of the scheme presented in Section II allows to estimate the quantum invariant Z L in constant time with an additive error that scales like 1/ √ R where R is the number of repetitions of the experiment, now independent of the number of crossings.…”
Section: Link Invariantsmentioning
confidence: 99%
“…It is well-known that the computation of the Tutte polynomial is NP-hard [16]. Also, evaluating TðG; x; yÞ for specific points ðx; yÞ is NP-hard except for the points on the hyperbola ðx À 1Þðy À 1Þ¼ 1 or when ðx; yÞ equals ð1; 1Þ; ðÀ1; À1Þ; ð0; À1Þ; ðÀ1; 0Þ; ði; ÀiÞ; ðÀi; iÞ; ðj; j 2 Þ; ðj 2 ; jÞ where j ¼ e ð2pi=3Þ for which it can be done in polynomial time [16,26].…”
Section: Introductionmentioning
confidence: 99%
“…Also, evaluating TðG; x; yÞ for specific points ðx; yÞ is NP-hard except for the points on the hyperbola ðx À 1Þðy À 1Þ¼ 1 or when ðx; yÞ equals ð1; 1Þ; ðÀ1; À1Þ; ð0; À1Þ; ðÀ1; 0Þ; ði; ÀiÞ; ðÀi; iÞ; ðj; j 2 Þ; ðj 2 ; jÞ where j ¼ e ð2pi=3Þ for which it can be done in polynomial time [16,26]. Vertigan [29] has extended this by showing that a similar result holds for planar graphs except that, in this case, for the additional points lying on the hyperbola ðx À 1Þðy À 1Þ¼ 2, the problem can be solved again in polynomial time.…”
Section: Introductionmentioning
confidence: 99%