“…(2) Similarly we make stellar subdivision at (3, 7) on L 0 at first, then make stellar subdivision at (1, 2, 3), the resulting set of missing faces of L ′ 2 is M ′ 2 = {(3, 7), (1,2,4,5,6,8,9), (1, 2, 3), (7, 10), (4,5,6,8,9,10)} . It is easy to see that two simplicial complexes K and K ′ on vertex set I are combinatorial equivalent if and only if their sets of missing faces M and M ′ are equivalent, i.e.…”