“…Hence we have X = {x 2 (t 2 )x 5 (t 5 ) | t 2 , t 5 ∈ F q , a 2 8 t 2 5 = a 9 t 2 and a 2 10 t 2 2 = a 18 t 5 } = {x 2 (t 2 )x 5 (t 5 ) | t 2 , t 5 ∈ F q , t 2 = a 2 8 a −1 9 t 2 5 and t 4 5 = a −4 8 a 2 9 a −2 10 a 18 t 5 } and Y = {x 3 (s 3 )x 7 (s 7 ) | s 3 , s 7 ∈ F q , a 9 s 2 3 = a 10 s 7 and a 18 s 2 7 = a 8 s 3 } = {x 3 (s 3 )x 7 (s 7 ) | s 3 , s 7 ∈ F q , s 7 = a 9 a −1 10 s 2 3 and s 4 3 = a 8 a −2 9 a 2 10 a −1 18 s 3 }. 15 Let us assume that f = 2k. If a 18 / ∈ a 8 a −2 9 a 2 10 F × q,3 , that is, for 2(q − 1)/3 choices of a 18 in F × q , then the quartic equations involved in the definitions of X and Y just have a trivial solution.…”
“…Hence we have X = {x 2 (t 2 )x 5 (t 5 ) | t 2 , t 5 ∈ F q , a 2 8 t 2 5 = a 9 t 2 and a 2 10 t 2 2 = a 18 t 5 } = {x 2 (t 2 )x 5 (t 5 ) | t 2 , t 5 ∈ F q , t 2 = a 2 8 a −1 9 t 2 5 and t 4 5 = a −4 8 a 2 9 a −2 10 a 18 t 5 } and Y = {x 3 (s 3 )x 7 (s 7 ) | s 3 , s 7 ∈ F q , a 9 s 2 3 = a 10 s 7 and a 18 s 2 7 = a 8 s 3 } = {x 3 (s 3 )x 7 (s 7 ) | s 3 , s 7 ∈ F q , s 7 = a 9 a −1 10 s 2 3 and s 4 3 = a 8 a −2 9 a 2 10 a −1 18 s 3 }. 15 Let us assume that f = 2k. If a 18 / ∈ a 8 a −2 9 a 2 10 F × q,3 , that is, for 2(q − 1)/3 choices of a 18 in F × q , then the quartic equations involved in the definitions of X and Y just have a trivial solution.…”
“…Then we define χ a 8 ,a 9 ,a 10 ,a 5,6,7 ,d 1,2,4 ,d 3 8,9,10,q 3 /2 by tensoring ψ d 1,2,4 with χ 0,0,d 3 ,0 lin . The proposition below states the values of these characters, these can be deduced from [30,Thm. 2.3].…”
Section: Qmentioning
confidence: 99%
“…2.3]. Note that with our specific choice of φ, we have ker [30,Definition 1.2]. In turn this implies that a φ as defined in [30,Definition 1.4] is equal to a −p .…”
Section: Qmentioning
confidence: 99%
“…Note that with our specific choice of φ, we have ker [30,Definition 1.2]. In turn this implies that a φ as defined in [30,Definition 1.4] is equal to a −p . We note that the values for χ a 8 ,a 9 ,a 10 8,9,10,q 3 look different to those for p > 2, which is explained by the fact that the quadratic Gauss sums for p = 2 are clearly zero.…”
Section: Qmentioning
confidence: 99%
“…to be the character obtained by inducing λ a 11 Using [30,Lemma 1.5] with Z = X 11 , Y = X 8 X 9 X 10 , X = X 1 X 2 X 4 and M = X 3 X 5 X 6 X 7 , we obtain that each χ a 11 ,b 5 ,b 6 ,b 7 ,b 3…”
Abstract. Let U be a Sylow p-subgroup of the finite Chevalley group of type D 4 over the field of q elements, where q is a power of a prime p. We describe a construction of the generic character table of U .
Let G be a simple algebraic group defined over an algebraically closed field of characteristic 0 or a good prime for G. Let U be a maximal unipotent subgroup of G and u its Lie algebra. We prove the separability of orbit maps and the connectedness of centralizers for the coadjoint action of U on (certain quotients of) the dual u * of u. This leads to a method to give a parametrization of the coadjoint orbits in terms of so-called minimal representatives which form a disjoint union of quasi-affine varieties. Moreover, we obtain an algorithm to explicitly calculate this parametrization which has been used for G of rank at most 8, except E 8 .When G is defined and split over the field of q elements, for q the power of a good prime for G, this algorithmic parametrization is used to calculate the number k(U (q), u * (q)) of coadjoint orbits of U (q) on u * (q). Since k(U (q), u * (q)) coincides with the number k(U (q)) of conjugacy classes in U (q), these calculations can be viewed as an extension of the results obtained in [11]. In each case considered here there is a polynomial h(t) with integer coefficients such that for every such q we have k(U (q)) = h(q). We also explain implications of our results for a parametrization of the irreducible complex characters of U (q).2010 Mathematics Subject Classification. 20G40, 20E45.
scite is a Brooklyn-based organization that helps researchers better discover and understand research articles through Smart Citations–citations that display the context of the citation and describe whether the article provides supporting or contrasting evidence. scite is used by students and researchers from around the world and is funded in part by the National Science Foundation and the National Institute on Drug Abuse of the National Institutes of Health.