2018
DOI: 10.1007/s11139-018-0045-4
|View full text |Cite
|
Sign up to set email alerts
|

On second and eighth order mock theta functions

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
2
1
1

Citation Types

1
6
0
2

Year Published

2020
2020
2024
2024

Publication Types

Select...
5
2

Relationship

0
7

Authors

Journals

citations
Cited by 11 publications
(9 citation statements)
references
References 17 publications
1
6
0
2
Order By: Relevance
“…The formula (1.15) was found by Cui, Gu and Hao [17] using Bailey pairs, and (1.17) is due to Gordon and McIntosh [23]. The representation (1.18) appears to be new, and in fact we will show that it is equivalent to (1.17) (see Section 8.5).…”
mentioning
confidence: 53%
See 1 more Smart Citation
“…The formula (1.15) was found by Cui, Gu and Hao [17] using Bailey pairs, and (1.17) is due to Gordon and McIntosh [23]. The representation (1.18) appears to be new, and in fact we will show that it is equivalent to (1.17) (see Section 8.5).…”
mentioning
confidence: 53%
“…Using Bailey pairs, Cui, Gu and Hao [17] provided Hecke-type series representations for mock theta functions of order 2. They also express these Hecke-type series in terms of f a,b,c (x, y, q).…”
Section: Mock Theta Functions Of Ordermentioning
confidence: 99%
“…By Theorem 2.4 m(−q 5 z 12 , q 12 , 1/qz 4 ) =m(−q 5 z 12 , q 12 , q 6 /z 12 ) + J 3 12 j(q 5 z 8 ; q 12 )j(−q 2 z 4 ; q 12 ) j(qz 4 ; q 12 )j(q 6 z 12 ; q 12 )j(−q 4 z 8 ; q 12 )j(−q 11 ; q 12 ) , and m(−1/qz 12 , q 12 , qz 4 ) =m(−1/qz 12 , q 12 , q 6 z 12 ) − qz 12 J 3 12 j(q 5 z 8 ; q 12 )j(−q 6 z 4 ; q 12 ) j(qz 4 ; q 12 )j(q 6 z 12 ; q 12 )j(−z 8 ; q 12 )j(−q 5 ; q 12 ) .…”
Section: So That (319)unclassified
“…So that g(z) = g 1 (z) − g 2 (z) where g 1 (z) := zj(qz 4 ; q 2 ) m(−q 5 z 12 , q 12 , q 6 /z 12 ) − 1 q 2 z 8 m(−1/qz 12 , q 12 , q 6 z 12 ) , and g 2 (z) := z 5 J 12 J 2 4 j(−qz 4 ; q 12 ) qJ 8 J 6 j(−z 8 ; q 12 )j(−q 4 z 8 ; q 12 ) J 2 12 J 8 J 2 24 J 4 j(q 14 z 8 ; q 24 ) 2 − q 2 J 2 24 J 6 J 2 4 J 2 12 J 8 J 2 j(q 8 z 8 ; q 12 ) − zJ 3 12 j(qz 4 ; q 2 )j(q 5 z 8 ; q 12 ) j(qz 4 ; q 12 )j(q 6 z 12 ; q 12 ) j(−q 2 z 4 ; q 12 ) j(−q 4 z 8 ; q 12 )j(−q 11 ; q 12 ) + z 4 j(−q 6 z 4 ; q 12 ) qj(−z 8 ; q 12 )j(−q 5 ; q 12 ) .…”
Section: So That (319)unclassified
“…We use the following Hecke-type series representation found by Srivastava [44, Eq. (5.4)] and Cui, Gu and Hao [19]:…”
Section: 23)mentioning
confidence: 99%