2014
DOI: 10.37236/4136
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On Saturated $k$-Sperner Systems

Abstract: Given a set X, a collection F ⊆ P(X) is said to be k-Sperner if it does not contain a chain of length k + 1 under set inclusion and it is saturated if it is maximal with respect to this property. Gerbner et al. [11] conjectured that, if |X| is sufficiently large with respect to k, then the minimum size of a saturated k-Sperner system F ⊆ P(X) is 2 k−1 . We disprove this conjecture by showing that there exists ε > 0 such that for every k and |X| ≥ n 0 (k) there exists a saturated k-Sperner system F ⊆ P(X) with … Show more

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Cited by 15 publications
(15 citation statements)
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“…Another related problem, following [8,15], is to determine the smallest maximal kcube free set in Z 2 n . That is, the smallest S ⊂ Z 2 n that is k-cube free, but the additon of any new element to S makes it not k-cube-free.…”
Section: Conclusion and Open Questionsmentioning
confidence: 99%
“…Another related problem, following [8,15], is to determine the smallest maximal kcube free set in Z 2 n . That is, the smallest S ⊂ Z 2 n that is k-cube free, but the additon of any new element to S makes it not k-cube-free.…”
Section: Conclusion and Open Questionsmentioning
confidence: 99%
“…Johnson and Pinto [27] also study another type of saturation problem, which is often referred to as semi-saturation [18,22] (other terms have also been used: see [10,28,32,34,36]). Given graphs F and H, say that a spanning subgraph G of F is (F, H)-semi-saturated if, for every edge e ∈ E(F) \ E(G), the graph G + e contains more copies of H than G does.…”
Section: Semi-saturationmentioning
confidence: 99%
“…A family A ⊆ P(X) is said to be F-saturated if there is no subfamily of A with the same poset structure as F, but adding any set to A destroys this property. Both the maximum and minimum size of such A have been studied: see for instance Katona and Tarján [8] for the former and Morrison, Noel and Scott [10] for the latter.…”
Section: Introductionmentioning
confidence: 99%