2005
DOI: 10.1007/s10468-004-6118-7
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On Primitive Ideals in Polynomial Rings over Nil Rings

Abstract: Let R be a nil ring. We prove that primitive ideals in the polynomial ring R [x] in one indeterminate over R are of the form I[x] for some ideals I of R.All considered rings are associative but not necessarily have identities. Köthe's conjecture states that a ring without nil ideals has no one-sided nil ideals. It is equivalent [4] It is known that if a polynomial ring R[x] is primitive then R need not be primitive [3] ( see also Bergman's example in [5]). Let R be a prime ring and I a nonzero ideal of R. Th… Show more

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Cited by 9 publications
(5 citation statements)
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“…[15]; however, this ring is not nil. Note that the polynomial ring in one indeterminate over Sasiada's ring is left and right primitive ( [44]). By Nakayama's lemma a simple Jacobson radical ring cannot be finitely generated.…”
Section: Simple Ringsmentioning
confidence: 99%
“…[15]; however, this ring is not nil. Note that the polynomial ring in one indeterminate over Sasiada's ring is left and right primitive ( [44]). By Nakayama's lemma a simple Jacobson radical ring cannot be finitely generated.…”
Section: Simple Ringsmentioning
confidence: 99%
“…A ring is said to be a Jacobson ring if every prime ideal of is an intersection of (either left or right) primitive ideals of . In [1] Now we recall some terminology and results; see [2][3][4]. A right ideal of a ring is called modular in if and only if there exists an element ∈ such that − ∈ for every ∈ .…”
Section: Introductionmentioning
confidence: 99%
“…Following [1] we have the following. We say that V is a "good number for ," if, for all sufficiently large , there are ∈ [ ; ] such that − ∈ with deg( ) ≤ V. Let ⊆ ; we denotẽ …”
Section: Introductionmentioning
confidence: 99%
“…In [2] this approximation was improved to become the Behrens radical, which lies between the Jacobson and Brown-McCoy radicals. Recently this was improved further in [17] by showing that if I is a primitive ideal in the polynomial ring R[x] in one indeterminate x over a nil ring R (the existence of such an ideal is equivalent to a negative solution of Köthe's problem), then I has the form of "polynomials over an ideal of R", namely, I = J [x] for some ideal J of R.…”
Section: Introductionmentioning
confidence: 99%