2005
DOI: 10.1016/j.disc.2004.05.022
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On pairs of permutable Hermitian surfaces

Abstract: We investigate the intersection R of two permutable Hermitian surfaces of PG(3, q 2 ), q odd. We show that R is a determinantal variety. From the combinatorial point of view R comprises a complete (q 2 + 1)-span of the two corresponding Hermitian surfaces.

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Cited by 11 publications
(13 citation statements)
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“…Every free generator π contains an (n − 2)-dimensional space π 1 lying in a pencil of q 2 + 1 hyperplanes P ⊥ ∩ π, P ∈ O, which cover all the points of π. 2 ) of size at most q 2 + q. The proof of the preceding theorem shows that every free generator π to O contains a point P lying on q 2 + 1 lines S ⊥ ∩ π, S ∈ O , covering all the points of π.…”
Section: Small Maximal Partial Ovoidsmentioning
confidence: 99%
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“…Every free generator π contains an (n − 2)-dimensional space π 1 lying in a pencil of q 2 + 1 hyperplanes P ⊥ ∩ π, P ∈ O, which cover all the points of π. 2 ) of size at most q 2 + q. The proof of the preceding theorem shows that every free generator π to O contains a point P lying on q 2 + 1 lines S ⊥ ∩ π, S ∈ O , covering all the points of π.…”
Section: Small Maximal Partial Ovoidsmentioning
confidence: 99%
“…Recently, attention was also paid to the problem of the cardinality of the smallest maximal partial ovoids and the smallest maximal partial spreads in finite classical generalized quadrangles and polar spaces [1,2,6,7,10,15,16]. In particular, [13,16] addressed these problems for the classical generalized quadrangles.…”
mentioning
confidence: 99%
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“…It turns out that the stabilizer of an elliptic congruence is actually the stabilizer of a complete (q 2 + 1)-span of H(3, q 2 ) as shown in [1], [2]. Notice that P SU 4 (q 2 ) has one or two classes of subgroups isomorphic to P Sp 4 (q) according as q is even or odd.…”
Section: Proofmentioning
confidence: 99%
“…In particular, there is no Baer elliptic quadric Q − (3, q) contained in O 3 , as any such quadric embedded in H must be a complete partial ovoid for even q (see [1], for instance). However, we can find a Baer elliptic quadric that will determine O 3 in an analogous fashion to the previous two cases.…”
Section: Proofmentioning
confidence: 99%