The Zassenhaus formula finds many applications in theoretical physics or mathematics, from fluid dynamics to differential geometry. The non-commutativity of the elements of the algebra implies that the exponential of a sum of operators cannot be expressed as the product of exponentials of operators. The exponential of the sum can then be decomposed as the product of the exponentials multiplied by a supplementary term which takes generally the form of an infinite product of exponentials. Such a procedure is often referred to as ``disentanglement''. However, for some special commutators, closed forms can be found. In this work, we propose a closed form for the Zassenhaus formula when the commutator of operators $\hX$ and $\hY$ satisfy the relation $[\hX,\hY]=u\hX+v\hY+c\mathbbm{1}$. Such an expression boils down to three equivalent versions, a left-sided, a centered and a right-sided formula:
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\begin{eqnarray}
e^{\hX+\hY}&=&e^{\hX}e^{\hY}e^{g_{r}(u,v)[\hX,\hY]}=e^{\hX}e^{g_{c}(u,v)[\hX,\hY]}e^{\hY}\nonumber\\
&=&e^{g_{\ell}(u,v)[\hX,\hY]}e^{\hX}e^{\hY},
\end{eqnarray}
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with respective arguments,
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\begin{eqnarray}
g_{r}(u,v)&=&g_{c}(v,u)e^{u}=g_{\ell}(v,u)\nonumber\\
&=&\frac{u\left(e^{u-v}-e^{u}\right)+v\left(e^{u}-1\right)}{vu(u-v)}
\end{eqnarray}
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for $u\ne v$ and 
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\begin{eqnarray}
g_{r}(u,u)=\frac{u+1-e^u}{u^2}\;\;\;\;\mathrm{with}\;\;\;\; g_r(0,0)=-1/2.
\end{eqnarray}
With additional special case
\begin{eqnarray} 
g_{r}(0,v)= -\frac{e^{-v}-1+v}{v^{2}}, \quad & g_{r}(u,0)=\frac{e^{u}(1-u)-1}{u^{2}}.
\end{eqnarray}