1971
DOI: 10.1007/bf02219979
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On locally finite groups of finite rank

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Cited by 55 publications
(24 citation statements)
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“…Thus R has finite rank and so, by [ It remains only to deal with the case where G is locally finite. By [14] G has an abelian subgroup A of infinite rank, and since A in turn has an infinite descending chain of subgroups of infinite rank it follows easily that there is a subgroup C of A such that C g is a proper subgroup of C for some g in G. But g has finite order n, say, and since C g i < C g i−1 for each positive integer i we obtain the contradiction that C = C g n < C. This completes the proof.…”
Section: Lemma 4 Let X Be a Finitely Generated Nilpotent-by-finite Gmentioning
confidence: 99%
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“…Thus R has finite rank and so, by [ It remains only to deal with the case where G is locally finite. By [14] G has an abelian subgroup A of infinite rank, and since A in turn has an infinite descending chain of subgroups of infinite rank it follows easily that there is a subgroup C of A such that C g is a proper subgroup of C for some g in G. But g has finite order n, say, and since C g i < C g i−1 for each positive integer i we obtain the contradiction that C = C g n < C. This completes the proof.…”
Section: Lemma 4 Let X Be a Finitely Generated Nilpotent-by-finite Gmentioning
confidence: 99%
“…As usual, γ i (X) denotes the ith term of the lower central series of a group X, and the Fitting radical Fitt(X) of X is the product of all normal nilpotent subgroups of X. (c) A locally finite group of finite rank is almost locally soluble, that is, it has a normal locally soluble subgroup of finite index [14]. Indeed, the same holds for locally (soluble-by-finite) groups, by [3] (see also [4]).…”
Section: Is Countable Then H and K May Be Chosen So That I G (H) = G mentioning
confidence: 99%
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“…In particular, if H is soluble then so is Kin other words, each insoluble section K of G has no soluble subgroups of infinite rank. Now a locally nilpotent group of infinite rank has an infinite rank abelian subgroup [7, Corollary 2 to Theorem 6.36], and the same holds for hyperabelian groups [1] and locally finite groups [12]. Again let K be an infinite rank section of G. If M is an infinite rank subgroup of K generated by K-invariant subgroups M λ of finite rank then, since each M λ has a characteristic and hence K-invariant abelian series [7,Lemma 10.39], M is hyperabelian and K is therefore soluble (since M has an abelian subgroup of infinite rank).…”
Section: The Proof Of Theoremmentioning
confidence: 99%
“…We may now apply a deep theorem of Sunkov (1971) to conclude that K has a locally soluble normal subgroup K o of finite index and finite rank. By Kargapolov (1959) …”
Section: B Let G Be a Locally Finite Group And Let N = Tt(g) Then Nmentioning
confidence: 99%