“…Thus 3 is a common index divisor of K. If a ≡ 7 (mod 3 5 ) and b ≡ 183 (mod 3 5 ) , then N + φ 2 (F) = S 21 + S 22 has two sides joining (0, 4), (2, 1), and (3, 0), with R λ 21 (F)(y) = −(y 2 + 1), which is irreducible over F 3 . Thus 3 is not a common index divisor of K. For a ≡ 88+3 6 A and b ≡ a 5 −a 3 (mod 3 6 ), we have F(x) ≡ φ 6 2 +(729A+1747)φ 5 2 + (1458A + 895)φ 4 2 + (729A + 60)φ b ≡ 5934 (mod 3 8 ), then N + φ 2 (F) has three sides joining (0, v), (1,4), (2, 1), and (3, 0). Thus φ 2 provides three prime ideals of Z K lying above 3 with residue degree 1 each, and so 3 is a common index divisor of K. (7) If a ≡ 11 (mod 3 5 ) and b ≡ 69 (mod 3 6 ) , then N + φ 2 (F) = S 21 + S 22 has two sides joining (0, v), (1,2), and (3, 0), with v ≥ 4 and R λ 22 (F)(y) = y 2 + y + 1 = (y − 1) 2 .…”