2012
DOI: 10.1016/j.topol.2011.10.014
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On inductive dimension modulo a simplicial complex

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Cited by 2 publications
(4 citation statements)
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“…The dimension M -Ind 0 modulo a simplicial complex M [respectively: modulo an ANR M ] is defined similarly as M -Ind-in order that M -Ind 0 X ≤ α we stipulate that the M -partition P in the statement 1.3 (b) [respectively: 1.4(b')] is a zero set with M -Ind 0 P < α (see [2, p. 670]). It is easily shown by transfinite induction that M -Ind ≤ M -Ind 0 , and Theorem 1 in [2] may be summarised as follows: K-Ind 0 = |K|-Ind 0 for any simplicial complex K and all normal spaces. Thus, we have n ≤ |∂∆ k |-Ind Z i ≤ |∂∆ k |-Ind 0 Z i = ∂∆ k -Ind 0 Z i .…”
Section: Compact Spaces Withmentioning
confidence: 99%
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“…The dimension M -Ind 0 modulo a simplicial complex M [respectively: modulo an ANR M ] is defined similarly as M -Ind-in order that M -Ind 0 X ≤ α we stipulate that the M -partition P in the statement 1.3 (b) [respectively: 1.4(b')] is a zero set with M -Ind 0 P < α (see [2, p. 670]). It is easily shown by transfinite induction that M -Ind ≤ M -Ind 0 , and Theorem 1 in [2] may be summarised as follows: K-Ind 0 = |K|-Ind 0 for any simplicial complex K and all normal spaces. Thus, we have n ≤ |∂∆ k |-Ind Z i ≤ |∂∆ k |-Ind 0 Z i = ∂∆ k -Ind 0 Z i .…”
Section: Compact Spaces Withmentioning
confidence: 99%
“…5 Fedorchuk's original K-Ind X and L-Ind X in [8] are natural numbers, −1, or ∞. Following [2], we allow both K-Ind X and L-Ind X to be an infinite ordinal.…”
Section: Notation Basic Definitions and Factsmentioning
confidence: 99%
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