“…By induction on n. First suppose n − d = 2. So if P ⊂ G be a diametrical path, then only one vertex of G is not in P. Note that two cycles of G should have a common vertex not in P and all other vertices of G should be in P, since every cycle has at least one vertex which is not in P. Therefore G ∈ B 3 and G = V r,s , is a quasi-tree graph introduced in [1]. The graph V r,s obtained by adding two paths of lengths r, s to two vertices of degree 2 of K − 4 , (see Figure 7).…”