1997
DOI: 10.1007/bf02674902
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On groups with infinitely many right orders

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Cited by 7 publications
(9 citation statements)
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“…, k} and every i ∈ N. Both cases being similar, we will consider only the former one. Following Zenkov [66], for each i ∈ N and each ω = (ℓ 1 , . .…”
Section: The Case Of Conradian Ordersmentioning
confidence: 99%
“…, k} and every i ∈ N. Both cases being similar, we will consider only the former one. Following Zenkov [66], for each i ∈ N and each ω = (ℓ 1 , . .…”
Section: The Case Of Conradian Ordersmentioning
confidence: 99%
“…Assuming Orb G (P ) is finite, we must have that Orb G (P ) is finite, and hence the stabilizer Stab G (P ) is a finite index subgroup of G that is biordered by the restriction of the left ordering < P . It follows that G is locally indicable [21], and hence has uncountably many left orderings, by [23].…”
Section: Now In Any Left Orderingmentioning
confidence: 99%
“…This case was settled in [13, Proposition 4.1] using ideas going back to Zenkov [15] and Tararin (see Kopytov and Medvedev [8]). …”
Section: Casementioning
confidence: 99%
“…Linnell's proof uses an argument from General Topology for reducing the general case to that of Conradian orderings for which prior arguments by Zenkov [15] apply. To deal with the non Conradian case, we use our machinery on Conradian souls.…”
Section: Introductionmentioning
confidence: 99%
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