1987
DOI: 10.1214/aos/1176350256
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On Adaptive Estimation in Stationary ARMA Processes

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Cited by 251 publications
(177 citation statements)
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“…We will therefore tacitly assume thatθ θ θ ∈ S k−1 (and thereforê ϑ ϑ ϑ = 1 m ⊗θ θ θ) is locally and asymptotically discrete throughout this section. Following Lemma 4.4 in Kreiss (1987), the local discreteness allows to replace in Part (iv) of Proposition 5.1 non-random perturbations of the form ϑ ϑ ϑ + n −1/2 ν ν ν (n) t (n) with t (n) such that ϑ ϑ ϑ + n −1/2 ν ν ν (n) t (n) still belongs to H 0 by a n 1/2 (ν ν ν (n) ) −1 -consistent estimatorθ ϑ ϑ := 1 m ⊗θ θ θ. Based on the asymptotic result of Proposition 5.1 and letting…”
Section: Proposition 51 Let Assumptions a B C And E Hold And Considermentioning
confidence: 99%
“…We will therefore tacitly assume thatθ θ θ ∈ S k−1 (and thereforê ϑ ϑ ϑ = 1 m ⊗θ θ θ) is locally and asymptotically discrete throughout this section. Following Lemma 4.4 in Kreiss (1987), the local discreteness allows to replace in Part (iv) of Proposition 5.1 non-random perturbations of the form ϑ ϑ ϑ + n −1/2 ν ν ν (n) t (n) with t (n) such that ϑ ϑ ϑ + n −1/2 ν ν ν (n) t (n) still belongs to H 0 by a n 1/2 (ν ν ν (n) ) −1 -consistent estimatorθ ϑ ϑ := 1 m ⊗θ θ θ. Based on the asymptotic result of Proposition 5.1 and letting…”
Section: Proposition 51 Let Assumptions a B C And E Hold And Considermentioning
confidence: 99%
“…This condition is however essential as it precisely allows to replace τ (4) and (5) by Lemma 4.4 in Kreiss (1987), where such replacements have been theoretically worked out in detail. Using this fact in combination with Slutsky's Lemma, we have the following crucial result.…”
Section: Construction Of Efficient Testing Proceduresmentioning
confidence: 99%
“…expansion (1.4) holds with φ(y) = r ρ (y). Efficient estimators for parameters of time series are constructed in Kreiss [9,10], Jeganathan [7], Drost et al [3] and Koul and Schick [8]. If we use an efficient estimatorρ forq w , then, by Theorem 2,q w (z) has influence function r z X 0 (ε 1 ) + S ρ 2 x (ψ * (ε 1 , z) − E[ψ * (ε, z)]) with r z = r ρ S ρ 2 xq (z).…”
Section: Efficiencymentioning
confidence: 99%