2014
DOI: 10.1007/s00010-014-0286-2
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Ohlin’s lemma and some inequalities of the Hermite–Hadamard type

Abstract: Abstract. Using the Ohlin lemma on convex stochastic ordering we prove inequalities of the Hermite-Hadamard type. Namely, we determine all numbers a, α, β ∈ [0, 1] such that for all convex functions f the inequalityis satisfied and all a, b, c, α ∈ (0, 1) with a + b + c = 1 for which we haveMathematics Subject Classification. Primary 26A51; Secondary 26D10, 39B62.

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Cited by 20 publications
(32 citation statements)
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“…Therefore a simple application of Ohlin's Lemma is impossible and an extra idea is needed. To handle such situations, in the papers [9,12], the authors employed the Levin-Stečkin theorem [6] (see also [7], Theorem 4.2.7). for all continuous convex functions f : [a, b] → R, it is necessary and sufficient that F 1 and F 2 satisfy the following three conditions: To start our considerations, we define the number of sign changes of a function ϕ : R → R by…”
Section: Casementioning
confidence: 99%
See 1 more Smart Citation
“…Therefore a simple application of Ohlin's Lemma is impossible and an extra idea is needed. To handle such situations, in the papers [9,12], the authors employed the Levin-Stečkin theorem [6] (see also [7], Theorem 4.2.7). for all continuous convex functions f : [a, b] → R, it is necessary and sufficient that F 1 and F 2 satisfy the following three conditions: To start our considerations, we define the number of sign changes of a function ϕ : R → R by…”
Section: Casementioning
confidence: 99%
“…Remark 1. Szostok noticed in [12] that if the measures µ X , µ Y corresponding to X , Y , respectively, are concentrated on the interval [a, b], then, in fact, the relation X cx Y holds if and only if the inequality (1.2) is satisfied for all continuous convex functions f : [a, b] → R.…”
Section: Introductionmentioning
confidence: 99%
“…In the paper [40], the author used Ohlin's lemma to prove some new inequalities of the Hermite-Hadamard type, which are a generalization of known Hermite-Hadamard type inequalities.…”
Section: Theorem 3 ([36]mentioning
confidence: 99%
“…This means that (42) provides an alternate proof of (41) (for twice differentiable f ). This new formulation of the Hermite-Hadamard inequality was inspiration in [32] to replace the middle term of Hermite-Hadamard inequality by more complicated expressions than those used in (40). In [32], the authors study inequalities of the form…”
Section: Inequalities Of the Hermite-hadamard Type Involving Numericamentioning
confidence: 99%
“…we can see that (2) is, in fact, an inequality involving two very simple quadrature operators and a very simple differentiation formula. In papers [11] and [12] the quadrature operators occurring in (2) were replaced by more general ones whereas in [9] the middle term from (2) was replaced by more general formulas used in numerical differentiation. Thus inequalities involving expressions of the form n i=1 a i F (α i x + β i y) y − x where n i=1 a i = 0, α i + β i = 1 and F ′ = f were considered.…”
Section: Introductionmentioning
confidence: 99%