2012
DOI: 10.1007/jhep02(2012)111
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Observations on open and closed string scattering amplitudes at high energies

Abstract: We study massless open and closed string scattering amplitudes in flat space at high energies. Similarly to the case of AdS space, we demonstrate that, under the T-duality map, the open string amplitudes are given by the exponential of minus minimal surface areas whose boundaries are cusped closed loops formed by lightlike momentum vectors. We show further that the closed string amplitudes are obtained by gluing two copies of minimal surfaces along their cusped lightlike boundaries. This can be thought of as a… Show more

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Cited by 18 publications
(27 citation statements)
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“…These equations have made an appearance at various times in the literature in a variety of different contexts [3][4][5][6][7][8][9][10][11]. The scattering equations generically have (n − 3)!…”
Section: Introductionmentioning
confidence: 99%
“…These equations have made an appearance at various times in the literature in a variety of different contexts [3][4][5][6][7][8][9][10][11]. The scattering equations generically have (n − 3)!…”
Section: Introductionmentioning
confidence: 99%
“…These equations have appeared a number of times in the literature in various contexts [18][19][20][21][22][23][24]. They are known to possess (n − 3)!…”
Section: Jhep02(2017)038mentioning
confidence: 99%
“…1 On the other hand, we must also have r i 1 = 1 because r 2 + · · · + r n = M = ord(D). 2 Hence the tableau for a r 1 ,··· ,r i−1 ,0,r i+1 ,··· ,rn has only the i-th row empty and all the other rows filled. The aforementioned preferred coloring leads to (n − 1) red tiles in total and the local duality relation represented by this colored tableau involves a r 1 ,··· ,r i 1 ,0,r i+1 ,··· ,rn and other coefficients that all have r i = 1, i.e.…”
Section: Jhep06(2017)015mentioning
confidence: 99%
“…The coefficients associated with the other three tableaux are worked out in the same fashion and take the following forms, a r 1 ,r 2 ,r 3 ,r 4 ,r 5 +1 = −1 ℓ 5 R(a r 1 ,r 2 ,r 3 ,r 4 ,r 5 +1 ) With all the coefficients fixed for the case of (3.17), it is now straightforward to evaluate the P 1 and B [1,2],1 terms in (3.14), by acting with the differential operator D. Explicitly, the P 1 term becomes The integrand term containing B [1,2],1 is holomorphically equivalent to…”
Section: E1mentioning
confidence: 99%
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