“…The coefficients associated with the other three tableaux are worked out in the same fashion and take the following forms, a r 1 ,r 2 ,r 3 ,r 4 ,r 5 +1 = −1 ℓ 5 R(a r 1 ,r 2 ,r 3 ,r 4 ,r 5 +1 ) With all the coefficients fixed for the case of (3.17), it is now straightforward to evaluate the P 1 and B [1,2],1 terms in (3.14), by acting with the differential operator D. Explicitly, the P 1 term becomes The integrand term containing B [1,2],1 is holomorphically equivalent to…”