2017
DOI: 10.1007/978-3-319-62127-2_7
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Obedient Plane Drawings for Disk Intersection Graphs

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Cited by 2 publications
(3 citation statements)
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“…Given a planar clustered graph C = (G, V), a disk arrangement D C that is not planar, i.e., D C satisfies condition (C1) and (C2) but not (P1) and (P2), and a D C -framed embedding ψ of G, is there a D Cframed straight-line drawing Γ that is homeomorphic to ψ and D C ? Note that if the disks D C are allowed to overlap (condition (P1)) and G is the intersection graph of D C , the problem is known to be N P-hard [6]. Thus, in the following we require that the disks do not overlap, but there can be disk-pipe intersections, i.e, D C satisfies conditions (C1), (C1) and (P1) but not (P2).…”
Section: Drawing On General Disk Arrangementsmentioning
confidence: 99%
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“…Given a planar clustered graph C = (G, V), a disk arrangement D C that is not planar, i.e., D C satisfies condition (C1) and (C2) but not (P1) and (P2), and a D C -framed embedding ψ of G, is there a D Cframed straight-line drawing Γ that is homeomorphic to ψ and D C ? Note that if the disks D C are allowed to overlap (condition (P1)) and G is the intersection graph of D C , the problem is known to be N P-hard [6]. Thus, in the following we require that the disks do not overlap, but there can be disk-pipe intersections, i.e, D C satisfies conditions (C1), (C1) and (P1) but not (P2).…”
Section: Drawing On General Disk Arrangementsmentioning
confidence: 99%
“…This requires that in the transition from ψ to Γ at any point in time an edge uv does not intersect a geometric object other than its own clusters. Note that if the disks D C are allowed to overlap and C is the intersection graph of D C , the problem is known to be N P-hard [6]. Thus, in the following we require that the disk may not overlap, but there can be disk-pipe intersection.…”
Section: A Drawing On Non-planar Disk Arrangementsmentioning
confidence: 99%
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