2003
DOI: 10.1090/qam/2019614
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Numerical approach to the waiting time for the one-dimensional porous medium equation

Abstract: Abstract.We consider the nonlinear degenerate diffusion equation. The most striking manifestation of the nonlinearity and degeneracy is an appearance of interfaces. Under some condition imposed on the initial function, the interfaces do not move on some time interval [0, t*]. In this paper, from numerical points of view, we try to determine the value of t*, which is called the waiting time.

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Cited by 4 publications
(3 citation statements)
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References 15 publications
(10 reference statements)
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“…For the waiting phenomenon, Mimura et al [21], Bertsch & Dal Passo [4] and Tomoeda & Mimura [32] estimated the waiting time by the interface, but the numerical interface actually has a velocity. Nakaki & Tomoeda [22] transformed the PME into another problem whose solution will blow up at a finite time, which is just the waiting time of PME. But the solution cannot be obtained after the waiting time.…”
mentioning
confidence: 99%
“…For the waiting phenomenon, Mimura et al [21], Bertsch & Dal Passo [4] and Tomoeda & Mimura [32] estimated the waiting time by the interface, but the numerical interface actually has a velocity. Nakaki & Tomoeda [22] transformed the PME into another problem whose solution will blow up at a finite time, which is just the waiting time of PME. But the solution cannot be obtained after the waiting time.…”
mentioning
confidence: 99%
“…Most of previous studies estimate the waiting time from the trajectory of numerical interface [55,6,43], but the numerical waiting time may not be clearly estimated in some cases. As an alternative approach, Nakaki and Tomoeda estimate the waiting time for the one-dimensional PME by transforming the original equation into another equation whose solution will blow up at the waiting time of the original PME [41]. Recently, Duan et al proposed an elegant criterion to determine the waiting time in one-dimensional case, and they manually set the velocity of interface to be zero before the numerical waiting time.…”
Section: Waiting Timementioning
confidence: 99%
“…On Ω = (0, π), the initial condition given by ρ 0 (x) = sin 2/(m−1) (x) if 0 ≤ x ≤ π, 0 otherwise, produces this behavior. It is shown in [40] that the corresponding solution has a waiting time of t * = m−1 2m(m+1) . As we choose m = 2, here t * = 0.08 3.…”
Section: Applications and Numerical Testsmentioning
confidence: 99%