“…The strength distribution is fitted by the sum of the μ-GR strengths of B 1 (μ,E 1 ) and B 2 (μ,E 2 ) given by 4) where E Gi and Γ i with i 1,2 are the resonance energy and the width for the ith GR, and the constant B i (μ) is given by σ i Γ i /(2π) with σ i being the total strength integrated over the excitation (Hashim et al, 2020). (A) When OMC on 100 Mo occurs, 100 Nb is excited to some energy up to around 50 MeV, with B n (B p ) 5.68 MeV (9.46 MeV), 6.87 MeV (8.34 MeV), 5.99 MeV (7.87 MeV) and 8.07 MeV (7.46 MeV) for Nb A with A 100, 99, 98, and 97, respectively.…”