1974
DOI: 10.1016/s0092-640x(74)80002-1
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Nuclear charge- and magnetization-density-distribution parameters from elastic electron scattering

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Cited by 1,388 publications
(433 citation statements)
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References 163 publications
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“…In this figure, the charge density of 208 Pb, tabulated in a number of compilations, is compared with the most recent one by Fricke et al [45]. Neglecting the oldest tabulation, differences of up to 50% are observed between Fricke et al, Jager et al [46], and de Vries et al [47] for radial distances close to 10 fm. We consequently use the Fricke charge distribution in this work.…”
Section: B Charge and Proton Distributionsmentioning
confidence: 87%
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“…In this figure, the charge density of 208 Pb, tabulated in a number of compilations, is compared with the most recent one by Fricke et al [45]. Neglecting the oldest tabulation, differences of up to 50% are observed between Fricke et al, Jager et al [46], and de Vries et al [47] for radial distances close to 10 fm. We consequently use the Fricke charge distribution in this work.…”
Section: B Charge and Proton Distributionsmentioning
confidence: 87%
“…If the charge distribution from Ref. [46] is used instead of that from Ref. [45], r np = 0.12 fm is obtained.…”
Section: Discussionmentioning
confidence: 99%
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“…The total transition energy deviates from the value reported in [7] because instead of using the Bethe logarithm reported in table I in [7] for calculating the transition frequency, an obsolete value from [10] has been used erroneously. The nuclear size contribution E FS has been calculated using a 7 Li charge radius of 2.39(3) fm [21,22] determined by elastic electron-scattering. According to [10], the field shift can be calculated from…”
Section: Introductionmentioning
confidence: 99%
“…[7], deconvoluted with the same proton form factor by the Fourier transform method. The same method has been used to extract the proton-point ground-state density from the charge density written as a parabolic Fermi distribution of the form with ro = 3.7984 fm, a = 0.5795 fm, and w = -0.1779 for 4oCa [7] and rq = 2.608 frn, a = 0.513 fm, and cu = -0.051 for~s O [8]. Then, assuming that the ground state and the transition densities of the neutron part is the same as that of the protons, we can calculate the form factor.…”
mentioning
confidence: 99%