1978
DOI: 10.1070/im1978v012n01abeh002289
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Normal Subgroups of Free Profinite Groups

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Cited by 28 publications
(13 citation statements)
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“…In [9], Fireman shows that proving this conjecture would in turn resolve a 1978 problem of Mel nikov [36]. We complete this work.…”
Section: Introductionmentioning
confidence: 73%
“…In [9], Fireman shows that proving this conjecture would in turn resolve a 1978 problem of Mel nikov [36]. We complete this work.…”
Section: Introductionmentioning
confidence: 73%
“…For each cardinal number m there exists a unique (up to an isomorphism) free pro-Σ-groupF m (Σ) of rank m. This group has a subset X of cardinality m which converges to 1 such that each continuous map ϕ 0 of X into a pro-Σ group G uniquely extends to a homomorphism ϕ :F m (Σ) → G. By Melnikov [Mel,Lemma 2.2],F m (Σ) has the embedding property [FrJ,p. 353 …”
Section: σ-Groupsmentioning
confidence: 99%
“…As n i ≥ 5 these groups A ni are simple. Hence Γ ∼ = A mj for some subsequence (m j ) of (n i ) (see [M;Lemma 1.3]; in fact Γ is the product of countably many copies of ∞ n=5 A n ). The fixed field of Γ in K is Hilbertian since it is an abelian extension of the Hilbertian field k [FrJ;Thm.…”
Section: Corollary 1: Suppose K Is a Countable Hilbertian Field Of Chmentioning
confidence: 99%