“…For these values of n, we choose the values of d and g listed in Table2such that the inequality q n/2 > 7W (d) 2 W (g) 2 S holds and get that (4, n) ∈ Q 2 (2, 2) unless n = 3, 4, 5, 6, 8, 10, 12, 15.Case k = 3 : In this case m = 1, 3, 7, 9, 21, 63 and Inequality (7) holds for i ≥ 5, when m = 1, for i ≥ 4, when m = 3, for i ≥ 3, when m = 7, 9 and for i ≥ 2, when m = 21, 63. Hence, (8, n) ∈ Q 2 (2, 2) unless n = 3, 4, 6, 7, 8, 9, 12, 14,16,18,21,24,28, 36, 42, 63, 126. For these remaining values, we directly verify the inequality q n/2 > 7W (q n − 1) 2 W (x n − 1) 2 and get that (8, n) ∈ Q 2 (2, 2) unless n…”