1987
DOI: 10.2307/2000673
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Nonsingular Quadratic Differential Equations in the Plane

Abstract: ABSTRACT. We consider the problem of determining the number of inseparable leaves of nonsingular polynomial differential equations of degree two. As a corollary of a classification theorem for the foliation defined by these equations, we prove that this number is at most 2.

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Cited by 3 publications
(5 citation statements)
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“…In this section we will state the main results on the classification of CS due to Cima and Llibre [3] .…”
Section: Classification Of Cubic Systemsmentioning
confidence: 99%
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“…In this section we will state the main results on the classification of CS due to Cima and Llibre [3] .…”
Section: Classification Of Cubic Systemsmentioning
confidence: 99%
“…Actually, a construction leading to examples with 2n -4 inseparable leaves for all n >_ 4 can be already found in [14] . In [3] it is claimed that the case n = 2 has at most 2 inseparable leaves. This claim is not true because in [7] the quadratic system x = 1 + xy, y = m-1y2 , with m G -1 has 3 inseparable leaves: y = 0 and the two branches of the hyperbola xy = -m/(m + 1).…”
Section: Introductionmentioning
confidence: 99%
“…The analysis of some of the cases in [1] is incomplete. In particular, in a case called (b2.2) in [1], the equation was reduced to (ey2 + ny +p)dx + [y(c'x + e'y)+m'x + n'y+p')dy = 0. It was claimed that for this to be nonsingular, one should have n2 -4pe < 0.…”
Section: Errata To "Nonsingular Quadratic Differential Equations In Tmentioning
confidence: 99%
“…As it was pointed out by Gasull and Llibre in [2], the correct value is 3. They also give the correct formulation of the theorem in [1] and its corollary, which should read as follows:…”
mentioning
confidence: 99%
“…In [CP2] it is studied the case n = 3. In [CP1] it is claimed that the case n = 2 has at most 2 inseparable leaves. This claim is not true because the easily integrable quadratic system x = 1 + xy, y = y2 /m with m < -1 studied in [GLL] has 3 inseparable leaves given by y = 0 and the two branches of the hyperbola xy = -m/{m + 1).…”
mentioning
confidence: 99%